49=25x^2

Solution for 49=25x^2 equation:

49=25x^2

We move all terms to the left:

49-(25x^2)=0

a = -25; b = 0; c = +49;
Δ = b2-4ac
Δ = 02-4·(-25)·49
Δ = 4900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4900}=70$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-70}{2*-25}=\frac{-70}{-50}
=1+2/5
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+70}{2*-25}=\frac{70}{-50}
=-1+2/5
$